x^2+30x-4000=x

Solution for x^2+30x-4000=x equation:

x^2+30x-4000=x

We move all terms to the left:

x^2+30x-4000-(x)=0

We add all the numbers together, and all the variables

x^2+29x-4000=0

a = 1; b = 29; c = -4000;
Δ = b2-4ac
Δ = 292-4·1·(-4000)
Δ = 16841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{16841}}{2*1}=\frac{-29-\sqrt{16841}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{16841}}{2*1}=\frac{-29+\sqrt{16841}}{2}
$